Measurement of a Hydrogen qubit?

Julian Blair
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Given a 2 state hydrogen atom in a superimposed state, how does one measure it for either of its two states?
 
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I don't think your question is well posed. In quantum mechanics the state of a system is not an "observable". The observables (the quantities that you measure in experiments) are represented by hermitian operators that act on the states of the system.
 
The energy eigenfunctions of a hydrogen atom are infinite - its not a two state system.

Thanks
Bill
 
OK, let me explain a bit better. The ground and 1st excited states of an Hydrogen atom are often given as an example of a qubit for use in quantum computing. The energies of these states are definitely eigenstates of the Hamiltonian. My question has to do with an Hydrogen qubit in a superimposed state comprising both the ground and 1st excited state. If this qubit has been altered via a quantum algorithm, then one would like to measure the probabilities that it is in state |0> or state |1>. How could this be done?
Of course this measurement would have to be re-done multiple times to arrive at an estimation of the probabilities.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

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