Fra said:
The problem I have here is that an observer can not measure it's own ignorance. If it could, it would instantly increase it's own information.
I don't think in terms of information, but I think everything in QJT can in principle be measured locally by a single observer.
There are three kinds of (partial) observables, all of which the observer can measure locally (notation as in previous post):
1. Time t, measured by a clock.
2. The Taylor coefficients \phi_m, measured by a local detector.
3. The base point q, measured e.g. by a GPS receiver. This is a somewhat weak point, since a GPS receiver does not function properly unless there are distant GPS satellites transmitting signals. Nevertheless, the actual measurement is local.
So all partial observables can be measured by local devices, living on the observer's worldline. From these we can construct complete observables \phi_m(t) and q(t), which are operators whose time evolution is predicted by the dynamics.
Fra said:
The uncertainty you refer to, is measured by a second observer.
I disagree. q(t) is an operator, to which the standard rules of QM apply. If we keep reading off the GPS receiver and the clock, there will be some fuzziness unless we are in an eigenstate.
However, the problem with a second observer does arise when we make contact with QFT. To this end, we must evaluate the Taylor series at some point x, i.e. construct the quantum field \phi(x,t). Here we must introduce an second, external observer, with two remarkable superpowers:
1. He is everywhere simultaneously, probing \phi(x,0) for all x when t = 0.
2. Nevertheless, he knows exactly where he is, without any quantum fuzziness (x is a c-number).
Such a superobserver is clearly unphysical, but only needs to be introduced when we ignore the physical observer and work with the observer-independent fields. The intrinsic jet formulation does not deal with the x's.
Despite dealing only with objects on the observer's trajectory, QJT should be almost as predictive as QFT, to the extent that we can identify fields with infinite Taylor series. One may guess that cases where the Taylor series does not converge, in some suitable operator sense, may well be in regions into which an observer cannot see, e.g. beyond an event horizon. Even if such regions are not unphysical per se, they are invinsible to the observer, and as such beyond the necessary scope of a physical theory.
Fra said:
A symmetry principles comes with hard constraints and high predictivity. But the understanding of WHICH symmetry is the correct one, and wether it's even timeless at all, is left out, replaced by ad hoc tricks. This is cured by the evolving picture, by trying to understand the origina of all symmetries in terms of rational inferences
The symmetry principle is really dictated by the correspondence principle. In the classical limit, QG must reduce to GR, and its symmetry principle must reduce to spacetime diffeomorphisms. The quantum symmetry must thus be some extension/anomaly of the classical symmetry. What else can it be? This is completely analogous to the classical bosonic string. It has an infinite conformal symmetry, which acquires an extension and becomes a Virasoro algebra in the quantum theory. If the quantum string had some entirely unrelated symmetry, or no symmetry at all, how could the classical limit come out right?
One can make an analogous discussion of Yang-Mills theory. The usual (inconsistent) QFT anomalies correspond to the so-called Mickelsson-Faddeev algebra. However, the algebra of gauge transformations possesses a second, observer-dependent type of extension, called the "central extension" in chapter 4 of Pressley-Segal "Loop groups" (it does not commute with diffeomorphisms, though). The two types of algebra extensions are discussed and contrasted in
http://arxiv.org/abs/math-ph/0501023.