Measures of Central Tendency & t-86

  • Thread starter Thread starter kuahji
  • Start date Start date
AI Thread Summary
The discussion focuses on using the TI-86 calculator to compute the mean and standard deviation for grouped data. The user successfully calculated the mean and standard deviation by hand but needed assistance translating this into the TI-86. They learned that they must enter the class midpoints into the xstat and the corresponding frequencies into the fstat to obtain accurate results. The confusion arose from mixing up xstat and ystat with fstat. Ultimately, the user clarified the correct method for inputting data into the calculator to achieve the desired statistical outputs.
kuahji
Messages
390
Reaction score
2
The statistics course I'm taking is a technology based course, & goes hand in hand with the ti-83. I happened to have a ti-86 & need some help.

I understand how to calculate the mean by hand & by the calculator for most circumstances. What I don't is when there are classes, for example

Class Frequency
10-19 8
20-29 16
30-39 21
40-49 11
50-59 4

Now, I can compute the approximate mean by hand with the formula in the book. The answer gives a mean = 32.83 & a standard deviation = 11.06. The answer checks with the back of the book. How can I place this information into the ti-86 & get the same results?
 
Physics news on Phys.org
You will have to enter a list. To solve the following problem, Enter a list of 8 15s 16 25s 21 35s etc. Then you can pull all the 1-Var Stats of this list. It should give you the proper mean, and variance.
 
Thanks for the help, what actually happened was I was getting the xstat & ystat mixed up with fstat... The classes as you pointed had to be placed in the xstat & then the frequency in the fstat. Seems kinda silly, not sure why I didn't get it before.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

Similar threads

Back
Top