Measuring energy and then momentum

Click For Summary
SUMMARY

The discussion focuses on the relationship between energy and momentum measurements in quantum mechanics, specifically in a potential well scenario. The user inquires about the outcome of measuring momentum after having measured energy, assuming the system is left in an energy eigenfunction. The response clarifies that a pure momentum measurement does not yield a single value but rather an expectation value, especially in a variable potential context. The user also specifies that the potential is zero, indicating a focus on a quantum well situation.

PREREQUISITES
  • Quantum mechanics fundamentals
  • Understanding of energy eigenfunctions
  • Familiarity with momentum operators
  • Knowledge of expectation values in quantum systems
NEXT STEPS
  • Study the implications of measuring energy eigenfunctions in quantum mechanics
  • Learn about the momentum operator in quantum mechanics
  • Explore expectation values and their calculations in quantum systems
  • Investigate the effects of variable potentials on momentum measurements
USEFUL FOR

Students of quantum mechanics, physicists exploring wave functions, and anyone interested in the principles of measurement in quantum systems.

Hypersquare
Messages
14
Reaction score
0
Hi there,

Im confused by something that came up in my quantum mechanics lecture. The lecturer posed us a question. What result do I get for a measurement of momentum if I have already measured the energy.

I assumed after measuring energy that the system would be left in an energy eigenfunction. So I tried to do the momentum operator on this eigenfunction (the one with sin in) and I have something that looks like:

[i [itex]\hbar[/itex]Cos([itex]n \pi x/\sqrt{a}[/itex])]/a

Is that correct? If so how do I extract the eigenvalues from it?

Thanks
 
Physics news on Phys.org
Eigenfunction where?
Your momentum measurement might depend on the position, if your potential is variable. A pure momentum measurement would not give a single, predictable value, but you could integrate over your whole wave function to get an expectation value.
 
Sorry I meant in the well, where the potential is zero.
 

Similar threads

  • · Replies 31 ·
2
Replies
31
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
4K