Mechanical energy required each cycle to operate the refrigerator

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SUMMARY

The discussion centers on calculating the mechanical energy required for a refrigerator with a coefficient of performance (COP) of 2.16, which absorbs 3.435×104 J from the cold reservoir. The user initially struggled with the equations e = W/Qh and e = 1 + (Qc/Qh) to find the heat discarded to the hot reservoir. The resolution involves recognizing that the total heat discarded (Qh) equals the heat absorbed (Qc) plus the work input (W), confirming the need for additional energy input to operate the refrigerator effectively.

PREREQUISITES
  • Understanding of thermodynamic principles, specifically the concept of coefficient of performance (COP).
  • Familiarity with the first law of thermodynamics and energy conservation.
  • Knowledge of heat transfer concepts, particularly between cold and hot reservoirs.
  • Proficiency in using thermodynamic equations related to refrigerators.
NEXT STEPS
  • Study the derivation of the coefficient of performance (COP) for refrigeration cycles.
  • Learn about the Carnot cycle and its implications for refrigeration efficiency.
  • Explore the relationship between work input and heat transfer in thermodynamic systems.
  • Investigate practical applications of refrigeration principles in real-world systems.
USEFUL FOR

Students studying thermodynamics, engineers designing refrigeration systems, and anyone interested in understanding the mechanics of heat transfer in refrigeration cycles.

wgd9891
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MODS close this thread down i figured out the answer myself

Homework Statement


A refrigerator has a coefficient of performance of 2.16. Each cycle it absorbs an amount of heat equal to 3.435×104 J from the cold reservoir.

i need to find a) the mechanical energy required each cycle to operate the refrigerator.
b)during each cycle how much heat is discarded to the high temperature reservoir.

Homework Equations


e = W/Qh; e=1+(Qc/Qh)

The Attempt at a Solution



i used the formula in b and apparently it isn't the answer. i also tried using 1-(Qc/Qh) to find Qh. it still didn't work. any other ideas?

thanks
 
Last edited:
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Well, the concept of a refridgerator is a device that moves energy from a cold reservoir to a hot reservoir. So, from this, you know the heat discarded in the hot reservoir has to be at least that removed from the cold reservoir. But you have to remember that you also have to put work into the system in order to get the heat to move from cold to hot, so there will be extra energy discarded into the hot reservoir that will be equal to the work put in. So can you find the total energy being dumped into the hot reservoir from this information?
 
wgd9891 said:
MODS close this thread down i figured out the answer myself

The moderators aren't generally watching all these threads. I believe the local custom is that, if you are satisfied with the resolution of your problem, you can edit your thread title by adding [SOLVED] at the beginning.
 

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