Mechanical Principles, question on linear expansion of aluminium.

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SUMMARY

The linear expansion of aluminium is quantified by its linear expansivity of 24 x 10-6 K-1. When an aluminium rod with a diameter of 12mm and a length of 1.2m is heated from 15 degrees Celsius to 120 degrees Celsius, it undergoes thermal expansion. The change in temperature is 105 degrees Celsius, which can be used to calculate the new dimensions of the rod using the formula for linear expansion.

PREREQUISITES
  • Understanding of linear thermal expansion principles
  • Familiarity with the formula for linear expansion: ΔL = α × L₀ × ΔT
  • Basic knowledge of temperature scales and conversions
  • Ability to perform unit conversions (e.g., mm to meters)
NEXT STEPS
  • Calculate the new diameter of the aluminium rod after heating
  • Determine the new length of the aluminium rod using the linear expansion formula
  • Research the effects of temperature on different materials' expansion coefficients
  • Explore practical applications of thermal expansion in engineering design
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Students studying mechanical principles, engineers involved in material science, and anyone interested in the thermal properties of metals.

RingwoodPye
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Homework Statement


Question: If the linear expansivity of aluminium is 24 x 10-6 K-1, how much does the aluminium expand during the heating?

Homework Equations


As far as additional information on the question goes;
An aluminium rod is heated from 15 degrees Celsius to 120 degrees Celsius. The dimensions of the aluminium rod are 12mm (diameter) x 1.2m long. The density of aluminium is 2700 kg per meters cubed.

The Attempt at a Solution


So far I'm completely stumped, we may have covered it but I literally cannot work it out.
 
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Hi RingwoodPye, welcome to PF.

The linear thermal expansion coefficient is the proportional increase in every (unconstrained) distance per degree temperature increase. That is, a value of 0 K-1 would mean no expansion, and a value of 1 K-1 would mean a 100% expansion per degree. Knowing this, can you calculate the new diameter and the new length?
 

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