Mechanical System: Kinetic Energy of a Rotating Bar with Gravity

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Goklayeh
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Consider a mechanical system (subject to gravity) consisting of an homogeneous bar, lying in the [tex]xy[/tex] -plane, of mass [tex]m[/tex], length [tex]\ell[/tex] and negligible section, with an extreme hinged in a fixed point [tex]P[/tex] of the [tex]y[/tex] axis. Now, suppose that the [tex]y[/tex]-axis is rotating with angular velocity [tex]\omega = \omega(t)[/tex]. What is the kinetic energy of the system?
 
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Hi Goklayeh! :smile:

(have an omega: ω :wink:)

KE of rigid body = rotational energy (about c.o.m.) plus energy of total mass with same velocity as c.o.m.

(or use the parallel axis theorem)