Mechanics - Springs and pulleys

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cupid.callin
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Homework Statement


Diagram of a frictionless massless pulley with a 7 kg block and a 6 kg block hanging on either side, each attached to a spring of constant K = 10 N/m, and a 5 kg block and a 4 kg block below the springs, with a string tied to the ground beneath the 4 kg block.



The Attempt at a Solution



I could say that (A)(B) are correct and (C) is wrong and i know 4kg block will have acceleration but i don't know how to find it.
 
Attachments
  • Diagram of a frictionless massless pulley with a 7 kg block and a 6 kg block hanging from opposite ends of a rope, each attached to a spring of constant 10 N/m, which connect to a 5 kg block and a 4 kg block; the 4 kg block is tied to a String anchored to the ground.
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Doc Al said:
Hint: What's the tension in the spring connected to the 4kg block?

Hi Doc Al
thanks for replying

I know i need to find kx to find acceleration

so initially kx = mg + T

and even if i apply Newton laws to rest of the blocks ... i can't find the extension
 
ok ...

let tension in upper string is T1 and string with 4kg is T2
and extension in left and right spring is x1 and x2
Handwritten working on lined paper: 4kg: kx2 = 4g + T2; 6kg: T1 = 6g + kx2; 7kg: T1 = 7g + kx1; 8kg: kx1 = 5g; then T1 = 5g + 7g = 12g; kx2 = 6g, 12g - 6g = 6g; 4a = kx2 - 4g = 6g - 4g = 2g; a = 5.
OH MY GOD

:biggrin::biggrin::biggrin:DOC AL ... YOU ARE MY HERO ! :biggrin::biggrin::biggrin:

:blushing:

And just one more question ,,, (just out of curiosity) ... what does AL means in Doc Al
 
Attachments
  • Handwritten working on lined paper: 4 kg: kx2 = 4g + T2; 6 kg: T1 = 6g + kx2; 7 kg: T1 = 7g + kx1; 5 kg: kx1 = 5g; therefore T1 = 5g + 7g = 12g; kx2 = 6g since 12g - 6g = 6g; 4 a(4kg) = kx2 - 4g = 6g - 4g = 2g; a = 5.
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cupid.callin said:
And just one more question ,,, (just out of curiosity) ... what does AL means in Doc Al
It's my name. Clever, eh? :wink:
 
Doc Al said:
It's my name. Clever, eh? :wink:
:bugeye:
And congrats ... you're going to reach 30,000 posts soon ... i guess maximum till now