Melting Ice: 200g Steel at 150°C on 0°C Ice

[Ry122]

200g of steel was placed on a big block of ice.
The ice was 0 degrees C.
The metal was 150 degrees C.
How much ice gets melted?

My attempt:
Q=mc(changeinT)
Q=.2(460)150
Q=13800

Q=ML
13800=M(3.34x10^5)
M=.041317 kg is melted
Is this correct?

 

[Kurdt]

Looks fine to me.

 

[Ry122]

If this piece of metal was circular with a radius of 4 cm. How deep would it sink into the ice?

My attempt:
M=.041317 kg is melted

Area of circle = pie x r^2 = pie x .04^2 = 5.02 x 10^-3 m
Now setup an equation to find the height of the cylinder made.
Find what volume this would be.
v=m/d
= .041317/920
= 4.49 x 10^-5
5.02 x 10^-3 x height = 4.49 x 10^-5
height = 8.944 x 10^-3m
= .89cm
Is this correct?