- #1
DavidSmith
- 23
- 0
Consider a poisson process one (P1) with a frequency 'a' and if it happens 'k' times you get (e^-a)(a^k)/k!
and then you have another posssion processs that happens in the same time frame of P1 called P2 with a frequency of 'b' and if it happens 'z' times you get (e^-b)(b^z)/z!
So what is the probability that P1 merges with P2?
For example if is observed that a computer breaks once every 2 days and a lightbulb goes out every 4 days what is the probability that in one week two computers will break at the exact same time 5 lightbulbs go out?
I know this problem has something to do with the poisson distribution but I don't know how to merge these events to get an answer.
I went to wikipedia and searched on the net and couldn't find any exmaples of such a problem that deals with two events.
I found somethign on wikipedia that says:
If N and M are two independent random variables, both following a Poisson distribution with parameters λ and μ, respectively, then N + M follows a Poisson distribution with parameter λ + μ.
I know the the probabilities of both events happening are less than the probability of just one, but I don't think you can just multiply the probability of event each together to get the final probability of both events happening at the same time.
and then you have another posssion processs that happens in the same time frame of P1 called P2 with a frequency of 'b' and if it happens 'z' times you get (e^-b)(b^z)/z!
So what is the probability that P1 merges with P2?
For example if is observed that a computer breaks once every 2 days and a lightbulb goes out every 4 days what is the probability that in one week two computers will break at the exact same time 5 lightbulbs go out?
I know this problem has something to do with the poisson distribution but I don't know how to merge these events to get an answer.
I went to wikipedia and searched on the net and couldn't find any exmaples of such a problem that deals with two events.
I found somethign on wikipedia that says:
If N and M are two independent random variables, both following a Poisson distribution with parameters λ and μ, respectively, then N + M follows a Poisson distribution with parameter λ + μ.
I know the the probabilities of both events happening are less than the probability of just one, but I don't think you can just multiply the probability of event each together to get the final probability of both events happening at the same time.
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