Siddhartha Peri said:
DC high current capability, 200 million amps, research study
Let's do total cross-sectional current:
I'll build a toroid of 10 gauge magnet wire; inside diameter 2 feet; outside diameter 6 feet; thickness 1 foot.
So the windings will have 2 square feet of cross section. For 10-gauge magnet wire, that's about 15000 turns.
Each turn will average 4pi feet - so 188,500 feet. For that quantity, I think I could get the wire at $0.40 per foot. So $75,400.
The resistance across this toroid will be very close to 188.5 ohms.
If I was to do this with a single toroid, the current would need to be 200Mamps/15000 = 13,333 amps.
But my budget is $250K, so I can stack three of these. Getting the current in each to 4,444 amps. So I will need 838KVolts at 13,333 Amps for 180msec to power this. 11.2GW for 180msec = 2G joules. (560 KWhours)
The copper is 14grams/foot. So total weight of all three toroids would be 3*14*188,500 grams = 7.92Mg.
Taking the thermal mass (or density) of copper at 38.46J/gC. We have a temperature rise of 2GJ/(38.46J/gC * 7.92Mg) = 6.6 degrees Centigrade.
So we won't met the toroids.
Average price for electricity in the US is $0.12. So the energy cost is $67.
I still have $25000 left in my budget to find a way to go from AC to 838KVDC.
When I worked in Ayer, MA, there was an AC/DC power converter next door for electricity coming in from Canada. It was basically a 5-acre electric circuit.
He needs to borrow that for 180msec.