Minimum Speed for Stunt Driver to Safely Jump Over Cars

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To determine the minimum speed for a stunt driver to safely jump over ten cars, the key is to calculate the time it takes to fall 1.25 meters vertically. This involves setting up two equations: one for vertical motion and another for horizontal distance. The horizontal distance of 20 meters must be covered in the same time it takes to fall. The driver must maintain a speed that allows them to travel this distance while descending. Understanding these components is crucial for solving the problem accurately.
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Homework Statement


A stunt driver sets a jump off a horizontal platform and over ten cars. The height of the platform is 1.25 m, and the total distance of the cars is 20.0 m. Find the minimum speed required to safely clear the cars.


Homework Equations


x - x initial = velocity X t + 1/2 a t squared (??)


The Attempt at a Solution


I tried to follow an example from the book but got confused because of the height difference (the book example did not have a change in y). I looked at solving for various vector components, but I was unsure of the angle...if the driver is going off a flat surface, would the angle be 0? I figured that the change in y = -1.25 m and the change in x = 20.0 m, but after trying a few things, I kept getting stuck. Please help! :smile:
 
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You have to set up two equations really. First you need to know how long it will take for the stunt rider to drop the 1.25 meters. Then you can work out how fast he needs to go to travel 20 meters horizontally in the time it takes for him to hit the ground again.
 
Oh, thank you so much. I hate it when the answer is staring me in the face. I appreciate the help!
 
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