I was reading through my textbook and it said that the angle between the axes of two inertial frames, one stationary and one moving at velocity v is supposed to be tan^-1(v/c). I assumed this would be easy to show, but after spending a couple of hours on this probably trivial problem, I can't for the life of me get the right answer.(adsbygoogle = window.adsbygoogle || []).push({});

I'm using the transformation:

ct' = ctcosh(a) -xsinh(a)

x' = -ctsinh(a) + xcosh(a)

y' = y

z' = z

where a is the 'rapidity function', tanh^-1(v/c) (not that I really understand what that is)

What I've done is choose a value of ct' and kept x' = 0 i.e. (0, ct'), because I'm supposed to be looking at the axes. I'm supposed to convert this into the other inertial frame, I think, but I'm really confused...

Anyone know the answer?

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# Minkowski diagram - the angle between axes

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