- #1
binbagsss
- 1,278
- 11
So a mobius transformation is defined as [itex]\frac{az+b}{cz+d}[/itex]=f(z).
Where ad-bc≠0.
My question is just deriving this condition ad-bc≠0.
I understand that the condition describes the case were the mapping leaves all points unchanged. This is described as undefined in some textbooks...(why is this, isn't it then just an identity map?)
But not by setting z=f(z).
I can't see why this condition would not equally be desribed by z=f(z)?
Many Thanks for any assistance.
Where ad-bc≠0.
My question is just deriving this condition ad-bc≠0.
I understand that the condition describes the case were the mapping leaves all points unchanged. This is described as undefined in some textbooks...(why is this, isn't it then just an identity map?)
But not by setting z=f(z).
I can't see why this condition would not equally be desribed by z=f(z)?
Many Thanks for any assistance.