- #1
grapheeene
- 1
- 0
Hi guys,
First of all, thank you for your help. I am new in Ansys and Fluent (less than a month), hoping to learn.
I am trying to model a simple and single surface reaction
CH4 (g) -> C(s) + 2H2 (g)
on a "CVD reactor" to grow C(s) (graphene, or graphite). The inlets are gases inyections of Ar and CH4 at the top of the CVD, and two thin parallel Cu surfaces are in the center (the catalyst), where C would be deposited. I am trying to model the growth of C(s) and the amount of H2 on the entire region, with and without thermodifussion (Soret).
The question is that I have some trouble with setting up the mixture and the reaction. I have a confusion with 'site' and 'solid' species in this case, and with reactions and mechanisms (since it's only superficial). I need the system to stop generating H2 when the surface is full of C(s).
Can you guys give me some basic steps to start this?? I don't know how to get the adsorption done. Do I need another reaction??
I guess this problem is not hard to be solved. Thanks so much for your help!
First of all, thank you for your help. I am new in Ansys and Fluent (less than a month), hoping to learn.
I am trying to model a simple and single surface reaction
CH4 (g) -> C(s) + 2H2 (g)
on a "CVD reactor" to grow C(s) (graphene, or graphite). The inlets are gases inyections of Ar and CH4 at the top of the CVD, and two thin parallel Cu surfaces are in the center (the catalyst), where C would be deposited. I am trying to model the growth of C(s) and the amount of H2 on the entire region, with and without thermodifussion (Soret).
The question is that I have some trouble with setting up the mixture and the reaction. I have a confusion with 'site' and 'solid' species in this case, and with reactions and mechanisms (since it's only superficial). I need the system to stop generating H2 when the surface is full of C(s).
Can you guys give me some basic steps to start this?? I don't know how to get the adsorption done. Do I need another reaction??
I guess this problem is not hard to be solved. Thanks so much for your help!