Moment of a Distributed Load on Beam, Scanned work and Diagram.

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SUMMARY

The discussion focuses on calculating the forces of reaction for a beam subjected to a triangularly distributed load. A key point raised is the incorrect use of a 22.5 ft length for a 1350 lb force, as the total load from the triangular distribution is not 1350 lbs. Participants emphasize the importance of recalculating the resultant load, which acts at the centroid of the triangular load rather than its center.

PREREQUISITES
  • Understanding of static equilibrium principles, specifically SUM of Y forces = 0.
  • Knowledge of calculating moments about a point, particularly SUM OF FORCES ABOUT POINT B = 0.
  • Familiarity with triangularly distributed loads and their resultant forces.
  • Ability to interpret and analyze structural diagrams.
NEXT STEPS
  • Review the calculation methods for triangularly distributed loads in structural analysis.
  • Learn about centroids and their significance in load distribution.
  • Study the principles of static equilibrium in beam analysis.
  • Explore software tools for structural analysis, such as SAP2000 or AutoCAD.
USEFUL FOR

Students of civil engineering, structural engineers, and anyone involved in analyzing beam reactions under distributed loads.

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Homework Statement


Determine the forces of reaction.

Homework Equations



SUM of Y forces=0
SUM OF FORCES ABOUT POINT B = 0

The Attempt at a Solution


My attempt is in the link, I scanned the diagram along with my work.
Thanks for the feedback, appreciated.

http://imgur.com/i3cB2 <-----

Link
 
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hello,

When calculating moments, why did you take length of 22,5 ft for force 1350?
 
The total load from the triangularly distributed load is not 1350 lbs. Recalculate that load, and please note that the resultant load of a triangularly distributed load acts at the centroid of that triangle (which is not at its center).
 

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