MHB Moment of Force F & P: Calculation & Solution

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The discussion centers on calculating the moment of forces F and P about points A, B, C, and D, with specific values of 200 kg and 165 kg, respectively. The numbers 5, 4, and 3 refer to the dimensions of a right triangle formed by the vector representing the force, where 4 is the horizontal distance, 3 is the vertical distance, and 5 is the hypotenuse. This triangle helps in determining the slope and direction of the force vector. The calculation assumes clockwise moments as positive. Understanding these values is crucial for accurate moment calculations.
bergausstein
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I just don't know where did the numbers 5,4, and 3 came from. please explain.

I'am asked to do this

assuming clockwise moments as positive, compute the moment of force F = 200 kg and force P = 165 kg about points A, B, C, and D.

the solution picture is here
 

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bergausstein said:
I just don't know where did the numbers 5,4, and 3 came from. please explain.

I'am asked to do this

assuming clockwise moments as positive, compute the moment of force F = 200 kg and force P = 165 kg about points A, B, C, and D.

the solution picture is here

That particular force is represented by a vector that goes 4 grid squares to the right and 3 grid squares up.
The triangle identifies its slope.
The hypotenuse of that triangle is 5.
 
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