Moment of Force F & P: Calculation & Solution

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SUMMARY

The discussion focuses on calculating the moment of forces F = 200 kg and P = 165 kg about points A, B, C, and D, using the principles of static equilibrium. The numbers 5, 4, and 3 refer to the dimensions of a right triangle formed by the vector representation of force F, where the horizontal leg measures 4 units, the vertical leg measures 3 units, and the hypotenuse, representing the resultant force, measures 5 units. This triangle is crucial for determining the moment arm and calculating the moments about the specified points.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Knowledge of moment calculations in physics
  • Familiarity with vector representation of forces
  • Basic geometry, specifically right triangles
NEXT STEPS
  • Study the calculation of moments in static systems
  • Learn about vector decomposition in physics
  • Explore the application of trigonometry in force analysis
  • Review examples of moment calculations about various points
USEFUL FOR

Students in physics, engineers working with static structures, and anyone involved in mechanics or force analysis will benefit from this discussion.

bergausstein
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I just don't know where did the numbers 5,4, and 3 came from. please explain.

I'am asked to do this

assuming clockwise moments as positive, compute the moment of force F = 200 kg and force P = 165 kg about points A, B, C, and D.

the solution picture is here
 

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bergausstein said:
I just don't know where did the numbers 5,4, and 3 came from. please explain.

I'am asked to do this

assuming clockwise moments as positive, compute the moment of force F = 200 kg and force P = 165 kg about points A, B, C, and D.

the solution picture is here

That particular force is represented by a vector that goes 4 grid squares to the right and 3 grid squares up.
The triangle identifies its slope.
The hypotenuse of that triangle is 5.
 

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