Moment of Inertia, for Load along Z-Z axis?

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SUMMARY

The discussion focuses on calculating the Moment of Inertia for a C-Channel subjected to loads along the Z-Z axis. Participants clarify that when the load is axial, the primary concern is P/A stresses, but if the loading is eccentric, it introduces weak axis bending stresses. The Perpendicular Axes Theorem is referenced, with specific inquiries about whether Izz can be calculated as Ixx + Iyy. The consensus indicates that Izz is relevant when considering torsional effects due to non-central loading.

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Assuming that I have a C-Channel

When the load acts along the X-X axis, we take Iyy for the Bending moment calculations. Similarly, when load acts along the Y-Y axis, we take Ixx. But if i have a load that acts on Z-Z axis, how do I calculate the Moment of Inertia?

PLS SEE THE ATTACHMENTS in the following SEQUENCE

FIRST : Attchmnt : TOP VIEW
SECOND : Attchmnt : DETAIL A
THIRD : Attchmnt : ELEVATION

My specific Doubts:

  1. Do I have to take Izz?
  2. If yes, is Izz=Ixx+Iyy (applying Perpendicular Axes Theorem)

Can Anyone help me?
 

Attachments

  • TOP VIEW.jpg
    TOP VIEW.jpg
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  • DETAIL A.jpg
    DETAIL A.jpg
    17.6 KB · Views: 1,414
  • ELEVATION.jpg
    ELEVATION.jpg
    19.8 KB · Views: 573
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Loading along the z axis would be axial loading (P/A stresses, not bending stresses) except if the axial loading is eccentrically applied (I am not sure if it is) , then it would create weak axis bending stresses as well.
 
Quote: Similarly, when load acts along the Y-Y axis, we take Ixx end quote

When load is along y-axis, this member will bend about xx but will also twist about zz because it is not being loaded through its shear centre. That involves Izz as well as Ixx/
 

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