Moment of Inertia of 4 Balls on Square Side

AI Thread Summary
The discussion focuses on calculating the moment of inertia of a system of four solid balls positioned at the corners of a square. The initial approach used the parallel axis theorem to account for the moment of inertia of two balls. Clarification was sought on why the term 2(2/5 mr^2) was included in the final equation. It was determined that this term represents the moment of inertia of the two balls located along the axis of rotation. The conversation concludes with an acknowledgment of the oversight regarding the contribution of these two balls to the overall moment of inertia.
erisedk
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Homework Statement


There are four solid balls with their centres at the four corners of a square of side a. The mass of each sphere is m and radius is r. Find the moment of inertia of the system about one of the sides of the square.

Homework Equations

The Attempt at a Solution


I= 2 (two balls) × [ 2/5 mr^2 (Icm) + ma^2 ] (just used parallel axis theorem)

However, in the answer,
I = 2 ( 2/5 mr^2 ) + 2×[ 2/5 mr^2 + ma^2 ]

Why have they added 2 ( 2/5 mr^2 ) ??
 
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Using the parallel axis theorem is good. I don't see it under 2. What does it look like and for what balls do you apply it ?
 
erisedk said:
There are four solid balls

Why have they added 2 ( 2/5 mr^2 ) ??
Consider the above two lines.
 
Ok, right!
I got it, thanks. I didn't consider moi of the two balls along the axis.
 
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