Hey. There's one thing I've always been wondering about when it comes to deriving the expression for the moment of inertia of a spherical shell.(adsbygoogle = window.adsbygoogle || []).push({});

Namely, why is the length of the infinitesimal cylinder used in the derivations (like here ) equal to ##R d \theta##, instead of ##R d \theta \cdot \sin(\theta)##? Afterall, ##R d\theta## isn't the actual height of the cylinder. The vertical component (the component in the direction of the axis of rotation) of ##R d\theta## is the length, which equals to ##R d \theta \cdot \sin(\theta)##.

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# Moment of inertia of a spherical shell

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