- 7,201
- 530
It is correct. Whenever you are summing moments about a point to find reaction forces, you can assume applied clockwise moments, and applied clockwise moments from forces, all as plus, or all as minus, and you get the same answer. I suggest however to assume clockwise moments as plus.fonseh said:is my working of RB(5) -30.71 - 15(5)(2.5) = 0 incorrect ?
Forget about upwards or downwards in this step when determining reaction forces. Just use cw as plus and ccw as minus.For moment about A , i have M(A) -RB(5) +30.71 + 15(5)(2.5) = 0 , thus , moment about A = RB(5) -30.71 - 15(5)(2.5) = 0 , RB = 43.64 up
I did in this way because for the left end of span , clockwise moment is positive ( cause the beam to bend upwards) ,
Once again, when determining reaction forces, keep it a simple set of rules: Consider clockwise moments, whether an applied moment couple or an applied 'force times distance moment about a point', as PLUS. And counterclockwise as MINUS.similarly , when finding moment about B , I assume anticlockwise as positive .(because anticlockwise moment causing the right span to bend upwards) Moment = M(B) -RA(5) + 30.71-15(5)(2.5) = 0 , 31.36 up
Or should I be consistent , keeping clockwise moment as positive and anticlockwise as negative or vice versa?
I will try to sum up the signage rules later with a sketch, when I get a moment.