Momentum and kinetic energy- pendulum component

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SUMMARY

The discussion centers on calculating the horizontal component of displacement for a pendulum after an 18-g bullet traveling at 230 m/s embeds itself in a 3.6 kg pendulum. The conservation of momentum equation, MaVa1 + MbVb1 = MtVt2, is utilized to find the pendulum's speed post-collision, which is determined to be 1.15 m/s. To find the horizontal displacement, participants recommend applying the conservation of energy principle to determine the height reached by the pendulum and using trigonometry to resolve the horizontal component from the final position diagram.

PREREQUISITES
  • Understanding of conservation of momentum
  • Familiarity with kinetic energy and potential energy equations
  • Basic trigonometry for resolving components
  • Knowledge of pendulum motion dynamics
NEXT STEPS
  • Study the conservation of energy principle in mechanical systems
  • Learn how to apply trigonometry in physics problems involving pendulums
  • Explore detailed examples of momentum conservation in collisions
  • Investigate the dynamics of pendulum motion and its energy transformations
USEFUL FOR

Physics students, educators, and anyone interested in understanding the mechanics of pendulum motion and energy conservation in collision scenarios.

JerG90
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Homework Statement



An 18-g rifle bullet traveling 230 m/s buries itself in a 3.6kg pendulum hanging on a 2.8-m-long string, which makes the pendulum swing upward in an arc. Determine the horizontal component of the pendulum's displacement.


Homework Equations



MaVa1 + MbVb1= MtVt2

k.e.= 1/2mv^2

p.e.= mgh

The Attempt at a Solution



I can find the velocity of the pendulum, but not the displacement:

230 m/s * .018= 4.4 kg m/s

4.4 kg m/s / 3.6018 kg = 1.15 m/s (speed of the pendulum with bullet after collision)

I just don't know how to find the component of the horizontal displacement. Any help would be greatly appreciated.
 
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Once you've got the speed of the pendulum you will know how much kinetic energy it has. Also you can assume the pendulm at its maximum arc displacement has traded all that kinetic energy for gravitational potential energy.
 
JerG90 said:

Homework Statement



An 18-g rifle bullet traveling 230 m/s buries itself in a 3.6kg pendulum hanging on a 2.8-m-long string, which makes the pendulum swing upward in an arc. Determine the horizontal component of the pendulum's displacement.


Homework Equations



MaVa1 + MbVb1= MtVt2

k.e.= 1/2mv^2

p.e.= mgh

The Attempt at a Solution



I can find the velocity of the pendulum, but not the displacement:

230 m/s * .018= 4.4 kg m/s

4.4 kg m/s / 3.6018 kg = 1.15 m/s (speed of the pendulum with bullet after collision)

I just don't know how to find the component of the horizontal displacement. Any help would be greatly appreciated.

230 m/s * .018= 4.14 kg m/s
<did you miss 1 in 4.14?>

use conservation of energy principle to find height, and then try drawing a diagram of the system @ its final position. Then you just need trigonometry to get the x component.
 

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