Momentum must be conserved, so this is true, right?

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Momentum is conserved in a closed system, meaning that in a collision between a light hydrogen molecule and a heavy water molecule, the momentum lost by one is equal to the momentum gained by the other. However, momentum is not conserved in open systems where external forces are present. In the example of a stone sliding down a frictionless hill, while its mechanical energy is conserved, its momentum increases due to the gravitational force acting on it. Therefore, when considering the stone alone, momentum is not conserved, but if the stone and Earth are treated as a system, momentum is conserved. Understanding the system boundaries is crucial for determining whether momentum conservation applies.
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True or False:
In a collision between a light hydrogen molecule and a heavy water molecule, the momentum lost by one molecule is exactly the same as the momentum gained by the other molecule.

Momentum must be conserved, so this is true, right?
 
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In physics, momentum is always conserved. You just have to think about two things. A) Is the system being considered closed? and B) What happens as a result of momentum conservation.
 
It seems to be a closed system to me

so isn't the momentum conserved making this true


so i can make sure I have this concept:
as a stone slides down a frictionless hill its mechanical energy is conserved but its momentum is not. true or false

well since we are not given any info on the velocity at the beginning or end and since the velocity is constantly changing we cannot make any assumptions about momentum thus this statement is true.
 
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Well we know velocity is increasing, and p=mv, so momentum is increasing. Like I said, momentum is always conserved, so an equal amount has to come from somewhere else.
 
so the first one is true and the second one is false?
 
Nabeshin said:
Like I said, momentum is always conserved, so an equal amount has to come from somewhere else.
Momentum is not always conserved. Momentum is conserved in a closed system, but not in an open system (i.e., one with external forces acting on it).
 
Hi StephenDoty,

Both of your true/false statements are true. As the stone slides down the hill, its momentum increases, so its momentum is not conserved.

Deciding on whether momentum is conserved or not depends critically on what your system is. If there are no forces on the system from outside the system, then momentum is conserved. If there is a net force acting on the system from the outside, then the momentum will change with time.

So for the stone going down the hill, the wording of the question means that we want to consider the stone by itself as the system. There is a net outside force (the force from the earth), so momentum is not conserved for the stone.

Momentum is conserved if we had chosen (stone+earth) as a system. The change in the stone's momentum is equal in magnitude and opposite in direction to the change in the Earth's momentum. (The Earth pulls on the stone and the stone pulls on the earth, in addition to the action/reaction normal forces between stone and hill.) The momentum of (stone+earth) is conserved as the stone slides down the hill.
 
good i have the concept then

thank you
 
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