Momentum of light in gravity field and other mediums

jartsa
Messages
1,582
Reaction score
141
Let's say 1 Kilogram of matter is converted into light, and all this light is reflected into one direction.

What is the momentum of the light? Mass of 1 kg times velocity c ?

Let's say the same light enters a piece of glass where the speed of light is 1/2 c. What is the momentum of the light now? 1 kg times 1/2 c ? And did the piece of glass absorb half of the momentum?

Let's say the light enters a gravity field where the gravitational time dilation factor is 1/2. Does the light give half of its momentum to the gravitating thing, similarly as light perhaps gave half of its momentum to the piece of glass?
 
Physics news on Phys.org
jartsa said:
Let's say 1 Kilogram of matter is converted into light, and all this light is reflected into one direction.

What is the momentum of the light? Mass of 1 kg times velocity c ?

Indeed, mc^2 = pc.

jartsa said:
Let's say the same light enters a piece of glass where the speed of light is 1/2 c. What is the momentum of the light now? 1 kg times 1/2 c ? And did the piece of glass absorb half of the momentum?

Yeah, that seems reasonable too.

jartsa said:
Let's say the light enters a gravity field where the gravitational time dilation factor is 1/2. Does the light give half of its momentum to the gravitating thing, similarly as light perhaps gave half of its momentum to the piece of glass?

So you are thinking about a photon climbing out of a potential well and losing it's momentum? See, the situation is a little different here as the incoming photon does not give its momentum away, but instead robs some from the gravitating body. Likewise, an escaping photon gives some of its momentum to the massive object.
 
clamtrox said:
So you are thinking about a photon climbing out of a potential well and losing it's momentum? See, the situation is a little different here as the incoming photon does not give its momentum away, but instead robs some from the gravitating body. Likewise, an escaping photon gives some of its momentum to the massive object.

Let us consider a spot light in a gravity well, aimed straight up. Let's say time dilation factor is 1/2 at the location of the spot light. An observer far away will say that light is accelerated to velocity 1/2 c in the spot light, and when light leaves the gravity well the velocity of the light increases by 1/2 c.

I would guess that the light source experiences a force when it accelerates the light to velocity 1/2 c, and the gravity source experiences an equal force when light accelerates from 1/2 c to c, when leaving the gravity field.

The pull of gravity on the light can be ignored, because there isn't any. There is no energy change of light caused by pull of gravity. That is discussed here: https://www.physicsforums.com/showthread.php?t=601102
For light energy and momentum are very much proportional things, so no change of energy of light -> no change of momentum of light -> no pulling of light.
 
I started reading a National Geographic article related to the Big Bang. It starts these statements: Gazing up at the stars at night, it’s easy to imagine that space goes on forever. But cosmologists know that the universe actually has limits. First, their best models indicate that space and time had a beginning, a subatomic point called a singularity. This point of intense heat and density rapidly ballooned outward. My first reaction was that this is a layman's approximation to...
Thread 'Dirac's integral for the energy-momentum of the gravitational field'
See Dirac's brief treatment of the energy-momentum pseudo-tensor in the attached picture. Dirac is presumably integrating eq. (31.2) over the 4D "hypercylinder" defined by ##T_1 \le x^0 \le T_2## and ##\mathbf{|x|} \le R##, where ##R## is sufficiently large to include all the matter-energy fields in the system. Then \begin{align} 0 &= \int_V \left[ ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g}\, \right]_{,\nu} d^4 x = \int_{\partial V} ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g} \, dS_\nu \nonumber\\ &= \left(...
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...
Back
Top