Momentum Ratio: Why is it Wrong?

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The discussion revolves around the incorrect application of momentum and kinetic energy equations in a physics problem. The initial attempt mistakenly assumed equal velocities for two objects, leading to an incorrect momentum ratio. Clarification is provided that different variables should be used for each object's velocity in the kinetic energy equations. The importance of maintaining algebraic forms until the final calculation is emphasized for accuracy and simplification. Ultimately, the correct approach involves using distinct variables and simplifying the expressions algebraically before substituting numerical values.
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Homework Statement



physicshomework.jpg

Homework Equations



KE = 1/2 M V2
P = M V

The Attempt at a Solution



p = mv
pcardinal = .0450vcardinal
pbaseball= .144vbaseball

0450vcardinal/144vbaseball
Why is this not the correct answer?

I know KE are equal so
KEcardinal= ½ .0450 v2
KEbaseball= ½ .144 v2

so .0450 v2 = .144 v2
how is knowing the KE are equal any helpful, and why is my original answer not right?
 
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Yes, the ratio of the momenta is mcardvcard/(mbasevbase), but you do not know what those velocities are. In your attempted answer you seem to have assumed they are the same.
In your KE equations you even used v for both velocities, ending up with a statement that is clearly not true.
Write the KE equations again, being careful to use different variables for the two velocities, and use them to find the velocity ratio.
 
haruspex said:
Yes, the ratio of the momenta is mcardvcard/(mbasevbase), but you do not know what those velocities are. In your attempted answer you seem to have assumed they are the same.
In your KE equations you even used v for both velocities, ending up with a statement that is clearly not true.
Write the KE equations again, being careful to use different variables for the two velocities, and use them to find the velocity ratio.

I know KE are equal so
KEcardinal= ½ .0450 vcardinal2
KEbaseball= ½ .144 vbaseball2

.0450 = vbaseball2
______ _________
.144 = vcardinal2
 
and now I take the square root to find vc/vbb and plug that into
mvc/mvbb ?
 
David112234 said:
and now I take the square root to find vc/vbb and plug that into
mvc/mvbb ?
Yes. (But it is better technique to keep everything algebraic, only plugging in numbers at the final step. This has many advantages.)
 
haruspex said:
Yes. (But it is better technique to keep everything algebraic, only plugging in numbers at the final step. This has many advantages.)

mc*√mbb
-------------------------------------
mbb*√mc

.0450√.144 / .144√.0450

Is this correct?
 
David112234 said:
mc*√mbb
-------------------------------------
mbb*√mc

.0450√.144 / .144√.0450

Is this correct?
Yes, but you can simplify that a little. I would move everything inside the square root function.
 
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haruspex said:
Yes, but you can simplify that a little. I would move everything inside the square root function.

√.002025*.144/ √.020736*.0450 = .5590169944
I put it in and it is correct. thank you
 
David112234 said:
√.002025*.144/ √.020736*.0450 = .5590169944
I put it in and it is correct. thank you
ok!
But I meant, simplify it while still in algebraic form. Never plug numbers in until the final step. Many advantages to be had.
 
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