Momentum transfer from a transiting bullet

AI Thread Summary
The discussion clarifies the difference between momentum and energy in the context of a bullet's impact. It emphasizes that the energy transferred during the impact is calculated by the change in kinetic energy, represented by the formula 1/2mU^2 - 1/2mV^2. It also points out that knowing the energy or momentum lost by the bullet does not provide the force applied to the target without additional information on time or distance. The impact force varies significantly depending on the target material, illustrating that the same energy loss can result in different force experiences. Understanding these concepts is crucial for accurate analysis of ballistic impacts.
wirenut67
Messages
15
Reaction score
0
deleted
 
Last edited:
Physics news on Phys.org
Well the energy which it transfers, assuming it's all given in heat/other energy to the target is it's loss in Kinetic Energy;

\frac{1}{2}mU^2 - \frac{1}{2}mV^2

where U is it's initial speed and V is it's final speed after the impact, is that what you're looking for?
 
You appear to be confused between "momentum" and "energy". ft-lbs is a measure of energy, NOT force. Also, knowing how much energy or momentum the bullet lost will NOT tell you the "force applied to the target". you would also need to know either the time or the distance in which the bullet lost momentum or energy. Energy is average force times distance. And "distance" depends upon the substance the target is made of. A person dropping, from a given height, onto a matress will lose exactly the same momentum and energy as a person dropping from the same height onto a steel plate but the force experienced will be a lot less.
 
deleted
 
Last edited:
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Let there be a person in a not yet optimally designed sled at h meters in height. Let this sled free fall but user can steer by tilting their body weight in the sled or by optimal sled shape design point it in some horizontal direction where it is wanted to go - in any horizontal direction but once picked fixed. How to calculate horizontal distance d achievable as function of height h. Thus what is f(h) = d. Put another way, imagine a helicopter rises to a height h, but then shuts off all...
Back
Top