Momentum transfer in a first class lever

AI Thread Summary
In a seesaw arrangement with masses m1, m2, and m3, the discussion focuses on how momentum is distributed among these masses. The force applied to the fulcrum mass m3 is influenced by the mass of m2, due to its inertia resisting changes in motion. Participants seek clarification on the term "momentum distribution" and its application in this context. The conversation highlights the need for a clearer definition of momentum distribution, especially during collisions between the masses. Understanding these dynamics is crucial for analyzing the system's behavior.
dE_logics
Messages
742
Reaction score
0
We have a seesaw arrangement, a mass m3 supports the fulcrum, we have mass m2 on one end, and a mass m1 fall on the other end with velocity v.

Considering the distance between the fulcrum and m1 is d and that of m2 is r, what will be the momentum distribution?
 
Physics news on Phys.org
I think -

How much the force is applied to m3 depends on m2's mass, cause the reason why force is applying on m3 is cause of m2's reluctance to change in motion (or cause of inertia).
 
Last edited:
dE_logics said:
We have a seesaw arrangement, a mass m3 supports the fulcrum, we have mass m2 on one end, and a mass m1 fall on the other end with velocity v.

Considering the distance between the fulcrum and m1 is d and that of m2 is r, what will be the momentum distribution?

Hi dE_logics! :smile:

i think nobody's answering because we don't understand the question :redface:

what do you mean by the "momentum distribution"?

what is the original question? :smile:
 
Momentum distribution between m1, m2 and m3.
 
Now how can I define momentum distribution?

When 2 bodies collide momentum gets distributed...i.e they undergo momentum distribution.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top