Dragonfall
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Is there an easy description for all the real to real functions that are order-preserving? I can only think of linear functions
The discussion centers on the characterization of order-preserving functions from the real numbers to the real numbers, with a focus on identifying a class of functions that are strictly increasing, efficiently computable, and yield uniformly distributed outputs when applied to pairs of inputs. Participants explore various definitions and implications of order-preserving functions, as well as the computational properties of proposed function classes.
Participants express differing views on the definitions and properties of order-preserving functions, particularly regarding uniform distributions and the implications of function decomposition. The discussion remains unresolved with multiple competing perspectives on the feasibility of the proposed approaches.
Limitations include the lack of clarity around the definition of "uniformly selected" functions from uncountable sets, as well as the implications of function decomposition on the ability to recover inputs. The discussion also highlights the complexity of achieving uniform distributions in various contexts.
What do you mean by "order-preserving?" Is it the idea that if a < b, then f(a) < f(b)? If so any function that is strictly increasing satisfies the latter inequality. If you mean something different, you need to clarify your question.Dragonfall said:Is there an easy description for all the real to real functions that are order-preserving? I can only think of linear functions
mfb said:Uniformly random where?
Every f is "decomposable" that way, simply set f_1(x)=f(x), f_2(x)=x (or vice versa).
Knowing only one of an arbitrary and unknown "decomposition" makes the task impossible - see my example, one of the functions could be just the identify function.
I think it would really help if you give more context. What do you actually want to do?
So who is supposed to know what? What is the protocol you want to use, and what is the result?Dragonfall said:I'm trying to come up with something similar for two ordered committed numbers.