Motion and the Warping of Space

  • Thread starter Thread starter daisey
  • Start date Start date
  • Tags Tags
    Motion Space
daisey
Messages
131
Reaction score
3
I was reading that a stationary observer measuring an object in (very fast) motion would determine the object to be shorter in the direction of travel, compared to the size of that object measured at rest. What actually causes this difference from the perspective of the observer?

Does the fast moving object appear shorter to the observer because the object is actually traveling a shorter distance because of the warped space the object is traveling through? :confused:

Daisey
 
Physics news on Phys.org
If a man is traveling in a spaceship and it is moving with the speed of relative to c, then several changes will occur.
For the guy in the ship, the space is appear to be bending towards it or in other words you can say that the distance is shortening for him. this will happen because of the increasement of mass of the ship at the speed relative to c (space-time fibre wraps the ship around it).
But for you, Daisey(who is watching the ship from her rooftops) the space didn't shortens but spaceship itself shortens in the direction of motion.
the cause of this is simple but hard to accept for the new ones in relativity and for those who still have problems with the constant speed of light in all reference frames.
yes, because of the constant speed of light i.e. 3,00,000 km/sec.
 
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...
ASSUMPTIONS 1. Two identical clocks A and B in the same inertial frame are stationary relative to each other a fixed distance L apart. Time passes at the same rate for both. 2. Both clocks are able to send/receive light signals and to write/read the send/receive times into signals. 3. The speed of light is anisotropic. METHOD 1. At time t[A1] and time t[B1], clock A sends a light signal to clock B. The clock B time is unknown to A. 2. Clock B receives the signal from A at time t[B2] and...
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...
Back
Top