(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A proton moves at 4.50 x 10^{8}m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 9.60 x 10^{3}N/C. Ignoring any gravitational effects, find (a) the time interval required for the proton to move 5.00 cm horizontally, (b) its vertical displacement during that time interval, and (c) the horizontal and vertical components of its velocity after it has traveled 5.00 cm horizontally.

2. Relevant equations

[tex]\vec{a}[/tex] = q[tex]\vec{E}[/tex] / m

3. The attempt at a solution

(a) Since it's moving at constant horizontal velocity, and the only force its encountering is a vertical force, would the particle continue to move at the constant horizontal speed? Which would mean that the time interval to move 5.00 cm is just its velocity / 5.00 cm??

(b) I don't know how to relate the electric field to the velocity. But I know that the initial vertical velocity is 0, right?

(c) If i was right in (a) then its horizontal component will be the same

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# Motion of a Charged Particle in an Electric Field

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