Motion of Charged Particles in Electric Fields

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SUMMARY

The discussion focuses on calculating the smallest distance between two electrons fired directly at each other at a speed of 3.5 x 10^6 m/s. The relevant equations include kinetic energy (Ek = 1/2mv^2) and electric potential energy (Ee = kq1q2/r). The user attempts to equate Ek and Ee to find the solution but encounters errors in their calculations. Clarification on the physical meaning of Ek, mass (m), and velocity (v) is requested to resolve the issue.

PREREQUISITES
  • Understanding of classical mechanics, specifically kinetic energy calculations.
  • Familiarity with electrostatics, particularly Coulomb's law and electric potential energy.
  • Basic knowledge of particle physics, especially the properties of electrons.
  • Proficiency in algebra for solving equations involving variables.
NEXT STEPS
  • Review the principles of kinetic energy and its application in particle motion.
  • Study Coulomb's law and its implications for electric forces between charged particles.
  • Learn how to derive and manipulate equations involving kinetic and potential energy.
  • Practice solving problems involving the motion of charged particles in electric fields.
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism and particle dynamics, as well as educators seeking to clarify concepts related to charged particle interactions.

simplicity12
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Homework Statement


3. Two electrons are fired at 3.5 x 10^6 m/s directly at each other.
a)Calculate the smallest possible between the two electrons.


Homework Equations


Ek= 1/2mv^2
Ee= kq1q2/r


The Attempt at a Solution


I made the Ek and the Ee equal, but i keep on getting the wrong answer. Can someone please help me?
 
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What does Ek represent physically? (what is m? v?)
 
Please show us your work so we can point out where the error is.
 

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