- #1
shaddix
- 1
- 0
Thanks to anyone who cares to read or respond. I've never taken a physics class so really all I have is "it seems to me". But I would like what seems to me to make sense.
Scenario. I have a motorcycle, in a steady-state corner(a circle), say 40 feet in diameter. And motorcycle is traversing the corner at a sustained 25mph. I'm trying to determine, what forces are acting on the bike. I really don't even know where to start with it. It seems to me that there is "camber thrust" from both tires, due to the fact the side of the tire is smaller than the centre. So that is doing something. And then the front tire is pointed to the inside of the turn, forcing the front of the bike to laterally accelerate in that direction as it goes around. And the back tire is providing forward motion.
So it seems to me that the majority of the cornering load is going to be on the front tire, and the back tire is basically just following the front of the bike around. Is that a correct supposition? So the practical effect of this is that if you were to let go of the handlebars, and crank the throttle wide open, you would simply exit the turn and go straight(the bike would stand up).
This also makes it seem like, you could lean the bike way over, open the throttle as much as you want, and as long as you don't change your lean angle, the back tire shouldn't slide out. Somehow I think there is less weight on the back tire when the bike is leaned over to allow for max throttle, but I can't figure out how.
Sorry this is such a jumble!
Scenario. I have a motorcycle, in a steady-state corner(a circle), say 40 feet in diameter. And motorcycle is traversing the corner at a sustained 25mph. I'm trying to determine, what forces are acting on the bike. I really don't even know where to start with it. It seems to me that there is "camber thrust" from both tires, due to the fact the side of the tire is smaller than the centre. So that is doing something. And then the front tire is pointed to the inside of the turn, forcing the front of the bike to laterally accelerate in that direction as it goes around. And the back tire is providing forward motion.
So it seems to me that the majority of the cornering load is going to be on the front tire, and the back tire is basically just following the front of the bike around. Is that a correct supposition? So the practical effect of this is that if you were to let go of the handlebars, and crank the throttle wide open, you would simply exit the turn and go straight(the bike would stand up).
This also makes it seem like, you could lean the bike way over, open the throttle as much as you want, and as long as you don't change your lean angle, the back tire shouldn't slide out. Somehow I think there is less weight on the back tire when the bike is leaned over to allow for max throttle, but I can't figure out how.
Sorry this is such a jumble!