# Moving exponent

1. Jan 4, 2010

### pamparana

Hello,

I am having trouble getting my head around this:

Can someone explain why
$$x^{x}$$ = $$e^{xlgx}$$

I cannot seem to understand why this is true. I am quite weak when it comes to handling exponentials. I dare say that I am terrified of e!

Also, would this also hold for a static power: so $$x^{a}$$

Thanks,

Luca

2. Jan 4, 2010

### rochfor1

Remember that for a > 0, $$\ln ( a^b ) = b \ln a$$ and the fact that exponentation and the natural logarithm are inverse functions.

3. Jan 4, 2010

### pamparana

That makes sense!

Many thanks!