MTW Ex 21.15 - Curvature independent of Lapse and Shift functions

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Understanding curvature is essential for tackling the problem presented in MTW Ex 21.15, as it measures how much a surface deviates from being flat. The discussion highlights concerns about the correctness of dynamic initial value equations 21.116 and 21.117, suggesting they should include ADM equivalents. Familiarity with the ADM formalism is recommended, as it aids in solving the dynamic initial value equations related to curved spacetime. Additional resources, such as textbooks or online tutorials, may provide further clarity on these concepts. A solid grasp of curvature will facilitate progress in solving the problem.
TerryW
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Homework Statement
I'm completely baffled as to where to start on this!
Relevant Equations
See attached image of MTW Ex 21.15
Can anyone out there give me a hint as to where to start with this problem?

I've been looking at it for a while and can't see a way forward.

What exactly is "the curvature itself" here?BTW I think the dynamic initial value equations 21.116 and 21.117 are incorrect. MTW should have inserted to ADM equivalents of these equations.

Any help would be appreciated.Regards
TerryW
Ex 21.15.png
 
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The best place to start with this problem is by understanding what the curvature itself is. Curvature is a measure of how much a surface or space is curved. It can be defined as the rate at which a line deviates from being straight. Once you understand what the curvature is, you can then begin to work on solving the dynamic initial value equations. You may find it helpful to review the ADM (Arnowitt–Deser–Misner) formalism, which is a set of equations used to describe the dynamics of curved spacetime in general relativity. This formalism can be used to solve the dynamic initial value equations. Additionally, you may find it helpful to consult other resources, such as textbooks or online tutorials, that provide more detailed solutions to the equations.
 
I want to find the solution to the integral ##\theta = \int_0^{\theta}\frac{du}{\sqrt{(c-u^2 +2u^3)}}## I can see that ##\frac{d^2u}{d\theta^2} = A +Bu+Cu^2## is a Weierstrass elliptic function, which can be generated from ##\Large(\normalsize\frac{du}{d\theta}\Large)\normalsize^2 = c-u^2 +2u^3## (A = 0, B=-1, C=3) So does this make my integral an elliptic integral? I haven't been able to find a table of integrals anywhere which contains an integral of this form so I'm a bit stuck. TerryW

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