- #1
Eeduh
- 14
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Hi,
I'm attempting to do a simulation of rigid bodies dynamics, and have ran into a problem.
It can and at some point will occur that multiple forces will be acting on a rigid body, at different points with different strength and under different angles.
Obviously, before translating these forces into translational and rotational acceleration, they should be somehow added for a correct result.
I do know how to add forces acting on 1 point, but I think this is a bit more tricky. I need to find out what the resulting force will be (my guess is the same as when they act upon 1 point), and secondly, what the new point will be this added force acts upon.
not really an equation, but for multiple forces at one point you can use the 'head to tail' adding method. Or for computation, make an weighed avarage of both the x and y components of all forces.
As mentioned before, I guess the resulting force will be the same as when all forces would be acting on one point. Furthermore, I have the idea that the point where the resulting force will be acting upon is an avarage of all points, somehow weighed by the strength of each of those forces. I can't seem to find nor figure out the exact equations.
Some help would be highly appreciated
I'm attempting to do a simulation of rigid bodies dynamics, and have ran into a problem.
Homework Statement
It can and at some point will occur that multiple forces will be acting on a rigid body, at different points with different strength and under different angles.
Obviously, before translating these forces into translational and rotational acceleration, they should be somehow added for a correct result.
I do know how to add forces acting on 1 point, but I think this is a bit more tricky. I need to find out what the resulting force will be (my guess is the same as when they act upon 1 point), and secondly, what the new point will be this added force acts upon.
Homework Equations
not really an equation, but for multiple forces at one point you can use the 'head to tail' adding method. Or for computation, make an weighed avarage of both the x and y components of all forces.
The Attempt at a Solution
As mentioned before, I guess the resulting force will be the same as when all forces would be acting on one point. Furthermore, I have the idea that the point where the resulting force will be acting upon is an avarage of all points, somehow weighed by the strength of each of those forces. I can't seem to find nor figure out the exact equations.
Some help would be highly appreciated