Multiple Pulleys and Multiple Weights Problem

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The discussion centers on solving for the tension (T) required to maintain equilibrium in a system of multiple pulleys and weights. The participant has drawn force diagrams and established relationships between tensions and weights, noting that T1 equals W1g and T3 equals W2g. They deduce that T2, which is equivalent to T, can be calculated as (W2g - W1g)/2. A clarification is made that if the weights are already given, they should not be multiplied by g. The conversation confirms the approach to solving the problem while addressing the nuances of weight versus mass in the equations.
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1. Homework Statement

Solve for T (The force required to keep the pulleys at equilibrium)

See attached image for pulley setup.

2. Homework Equations

W2>W1
N=mg

3. The Attempt at a Solution

Currently I have drawn out all the forces that act on each pulley, and I know there is a way to set up the tensions to solve for T, but since no numerical values are given its a little more complicated.
After applying force diagrams to the hanging weights I got T1=W1g and T3=W2g (with T1 being the tension between Pulley 1 and weight 1, and T3 being the tension between Pulley 2 and weight Which would mean T2=(W2g-W1g)/2, and T2 is the same tension as T, meaning T2 is equivalent to the downward force needed to keep the system at equilibrium. Is this the correct solution?
 
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for some reason the attachment wouldn't load in original post so here it is again.
 

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That's right, except that if the Ws are weights, not masses, then you don't multiply by g.
 
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Okay makes sense, thanks for confirming.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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