Multiplying Rational Expressions

AI Thread Summary
The discussion focuses on the multiplication of rational expressions, specifically the problem involving the expression (1+4x+4x^2)/x multiplied by 3x^4/(12x^2-3). The user initially simplifies incorrectly, resulting in an incorrect answer. A participant points out the need for careful factoring and suggests writing out all steps clearly. The correct factoring leads to the answer x^3(1+2x)/(2x-1), emphasizing the importance of thoroughness in mathematical processes. The conversation highlights common mistakes in factoring and simplification.
wScott
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This is a question I have to do for tomorrow

\frac{1+4x+4x^2}{x}\times\frac{3x^4}{12x^2-3}.

I just factor the tops and then cancel where I can. This is what I came up with:

\frac{3x^4}{12x^3-3x}

But the answer key says:

\frac{x^3(1+2x)}{2x-1}

What have I done wrong?
 
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wScott said:
This is a question I have to do for tomorrow

\frac{1+4x+4x^2}{x}\times\frac{3x^4}{12x^2-3}.

I just factor the tops and then cancel where I can. This is what I came up with:

\frac{3x^4}{12x^3-3x}

But the answer key says:

\frac{x^3(1+2x)}{2x-1}

What have I done wrong?

You aren't factoring carefully enough. You've got leftover factors floating around. Write out ALL of the steps!

\frac{1+4x+4x^2}{x}\times\frac{3x^4}{12x^2-3}

=\frac{(2x+1)(2x+1)}{x} \times \frac{3x^4}{3(2x-1)(2x+1)}

NOW do your cancelling.

-Dan
 
Ouch. That hurt my pride. I forget to factor the factor usually, that's going to kill me one day.

thanks for pointing out that pesky little mistake.
 
wScott said:
Ouch. That hurt my pride. I forget to factor the factor usually, that's going to kill me one day.

thanks for pointing out that pesky little mistake.

Happens to the best of us. No worries, mate! :biggrin:

-Dan
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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