Multivalued limit of (i + i/n)^n

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The discussion centers on the multivalued limit of the expression (i + i/n)^n as n approaches infinity, which approaches four discrete values: e, ei, -e, and -ei when n is an integer. The conversation highlights the confusion around why ei does not equal this limit, noting that e^i is defined as the limit of (1 + i/n)^n. Participants suggest that replacing n with a real number x may clarify the concept, referring to a limit cycle in the complex plane. The mention of a limit cycle indicates a circular behavior in the complex values involved. Overall, the discussion seeks to understand the nature of these limits and their definitions in complex analysis.
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I realized that (i + i/n)n approaches 4 discrete values (e, ei, -e and -ei) as n approaches infinity (if n is integer). (If I take that i2 = 1, then it approaches two discrete values (e and ei)). Does this kind of "multivalued limit" have some other name so I can learn more about it or where it has been applied ?

Why is ei not equal to this limit (since e1 is equal to the limit (1 + 1/n)n as n approaches inifinity) ? I know it's a matter of definitions but why isn't it defined this way ?

Thanks
 
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Hi ff,

"approaches 4 discrete values" is a little bit self-contradictory. Perhaps it's more sensible in this case to replace n by x (x a real number) and speak of a limit cycle (the circle ##|{\bf z}| = 1##) in the complex plane

"Why is ei not equal to this limit (since e1 is equal to the limit (1 + 1/n)n as n approaches inifinity) ?"

That is because ##e^i = \lim \,({\bf 1}+i/n)^n\ \ \ ## :smile:

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Hi BU,
BvU said:
Perhaps it's more sensible in this case to replace n by x (x a real number) and speak of a limit cycle (the circle ##|{\bf z}| = 1##) in the complex plane

Thanks for the "cycle". I think you meant ##|{\bf z}| = e## in this case though.
 
I certainly do :smile: ! Sorry for the mistake.
 
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