Multivariable calculus, partial derivatives

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Feodalherren
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Homework Statement


Untitled.png



Homework Equations





The Attempt at a Solution


Umm can somebody explain to me what just happened. None of that makes any sense to me what so ever.
 
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Of course. The notation in this problem is so confusing that I can't follow what's happening.
 
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Correct?
 
Ok I have no idea.. I can't remember what FoG means :/. You didn't even define F as anything?
 
Feodalherren said:
Ok I have no idea.. I can't remember what FoG means :/. You didn't even define F as anything?

##F## is just an arbitrary differentiable map (as shown in the problem statement).

What ##F\circ G## means is that it is the map which sends ##(s,t)## to ##F(G(s,t))##.

Can you show me the chain rule you've learned (and perhaps the variations)?
 
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I've only learned the one that I demonstrated. You draw one of those trees and then just differentiate however many times you need to in order to get to the variable that you need.

I'm totally lost on the notation yet again.
 
Feodalherren said:

Homework Statement


Untitled.png



Homework Equations





The Attempt at a Solution


Umm can somebody explain to me what just happened. None of that makes any sense to me what so ever.

Is the "subscript" notation throwing you off? If so, forget it and use a more exact nomenclature: ##W = F(u,v)## gives
[tex]\frac{\partial W}{\partial s} = \frac{\partial F}{\partial u} \frac{\partial u}{\partial s}<br /> + \frac{\partial F}{\partial v} \frac{\partial v}{\partial s}\: \longleftarrow \text{ chain rule}\\ <br /> \text{ }\\ \text{or}\\ <br /> \text{ }\\<br /> W_s = F_u u_s + F_v v_s[/tex]
etc.
 
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Ok that helps Ray. Now for the evaluation.

If I know Ws (1,0) then
s=1, t=0

Then I get:
u (1,0) and s (1,0).

Where do I evaluate the first therm dF/du?