Multivariable Optimization - Closest point on surface

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theWapiti
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Homework Statement



Find the first-octant point P(x,y,z) on the surface closest to the given fixed point Q (0,0,0).
The surface x2y2z=4

Homework Equations



gif.latex?d%3D%5Csqrt%7Bx%5E2%2By%5E2%2B(%5Cfrac%7B4%7D%7Bx%5E2y%5E2%7D)%5E2%7D.gif
is the distance along PQ.

EDIT:

2By%5E2%2B(%5Cfrac%7B4%7D%7Bx%5E2y%5E2%7D)%5E2%3Dx%5E2%2By%5E2%2B%5Cfrac%7B16%7D%7Bx%5E4y%5E4%7D.gif


The Attempt at a Solution



gif.latex?z%3D%5Cfrac%7B4%7D%7Bx%5E2y%5E2%7D.gif


frac%7B64%7D%7Bx%5E5y%5E4%7D%3D0%5C%5C%0A%5C%5Cx%3D%5Cfrac%7B2%7D%7By%5E%5Cfrac%7B4%7D%7B6%7D%7D.gif


I get stuck here every time. I feel like I'm just selling myself short here, but I don't know how to resolve the situation for when the critical point has a variable in it.
 
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theWapiti said:

Homework Statement



Find the first-octant point P(x,y,z) on the surface closest to the given fixed point Q (0,0,0).
The surface x2y2z=4

Homework Equations



gif.latex?d%3D%5Csqrt%7Bx%5E2%2By%5E2%2B(%5Cfrac%7B4%7D%7Bx%5E2y%5E2%7D)%5E2%7D.gif
is the distance along PQ.

The Attempt at a Solution



gif.latex?z%3D%5Cfrac%7B4%7D%7Bx%5E2y%5E2%7D.gif


frac%7B64%7D%7Bx%5E5y%5E4%7D%3D0%5C%5C%0A%5C%5Cx%3D%5Cfrac%7B2%7D%7By%5E%5Cfrac%7B4%7D%7B6%7D%7D.gif


I get stuck here every time. I feel like I'm just selling myself short here, but I don't know how to resolve the situation for when the critical point has a variable in it.

Your derivative is incorrect. Try again, more slowly this time.

When you've done that, then take the partial with respect to y (this should be easy because the problem is symmetric, so you just need to swap the x and y variables in your partial with respect to x) and set that equal to 0 as well. You then have two equations in two unknowns.
 
Mentallic said:
Your derivative is incorrect. Try again, more slowly this time.

When you've done that, then take the partial with respect to y (this should be easy because the problem is symmetric, so you just need to swap the x and y variables in your partial with respect to x) and set that equal to 0 as well. You then have two equations in two unknowns.

I feel like I'm probably just making myself problems here, but I can't for the life of me get past this still.

I was minimizing for the distance squared, which gave the two partials. But how can I solve if I have y in terms of x and x in terms of y?!
 
Well I feel like a dummy. Got it now, obviously. Sometimes the problem is made so much more difficult in your own mind!