Mutual Inductance Between a Coil and a Solenoid

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SUMMARY

The mutual inductance \( M_2 \) between a small coil with \( N_2 \) loops and a solenoid with \( N_1 \) loops is defined as \( M_2 = \frac{N_2 \phi_2}{I_1} \), where \( \phi_2 = BA_2 \cos(\theta) \). The correct expression for mutual inductance incorporates \( \sin(\theta) \) instead of \( \cos(\theta) \) due to the definition of the angle between the plane of the coil and the axis of the solenoid, which relates to the normal of the coil's plane. This distinction is crucial for accurately calculating magnetic flux in this context.

PREREQUISITES
  • Understanding of mutual inductance and its formula
  • Familiarity with magnetic flux and its calculation
  • Knowledge of the geometry of coils and solenoids
  • Basic principles of electromagnetism, particularly related to angles and planes
NEXT STEPS
  • Study the derivation of mutual inductance formulas in electromagnetic theory
  • Explore the role of angles in magnetic flux calculations
  • Learn about the significance of normal vectors in physics
  • Investigate practical applications of mutual inductance in electrical engineering
USEFUL FOR

Students of electromagnetism, electrical engineers, and anyone involved in the design and analysis of inductive components in circuits.

asap9993
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Homework Statement



A small, thin coil with N2 loops, each of area A2, is placed inside a long solenoid, near its center. The solenoid has N1 loops in its length L and has area A1. Find the mutual inductance as a function of θ, the angle between the plane of the small coil and the axis of the solenoid.

Homework Equations


M2 = N2\phi2/I1
\phi2 = BA2cos(θ) = μ0(N1/L)I1A2cos(θ)

The Attempt at a Solution


If we just substitute for \phi2 into the equation for M2, we get that
M2 = (N2/I1)BA2cos(θ) = μ0(N1N2/L)A2cos(θ)

Everything is right here except that the correct solution has sin(θ) instead of cos(θ). Why is that? Isn't the magnetic flux defined as a dot product?
 
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asap9993 said:

Homework Statement



A small, thin coil with N2 loops, each of area A2, is placed inside a long solenoid, near its center. The solenoid has N1 loops in its length L and has area A1. Find the mutual inductance as a function of θ, the angle between the plane of the small coil and the axis of the solenoid.

Homework Equations


M2 = N2\phi2/I1
\phi2 = BA2cos(θ) = μ0(N1/L)I1A2cos(θ)

The Attempt at a Solution


If we just substitute for \phi2 into the equation for M2, we get that
M2 = (N2/I1)BA2cos(θ) = μ0(N1N2/L)A2cos(θ)

Everything is right here except that the correct solution has sin(θ) instead of cos(θ). Why is that? Isn't the magnetic flux defined as a dot product?
I think it has to do with the wording, "the angle between the plane of the small coil and the axis of the solenoid."

The axis of the small coil is perpendicular to the plane of the same, small coil.
 
asap9993 said:

Homework Statement



" ...the angle between the plane of the small coil and the axis of the solenoid. "

Everything is right here except that the correct solution has sin(θ) instead of cos(θ). Why is that? Isn't the magnetic flux defined as a dot product?

You are right. When speaking of the angle a plane makes with another direction, the normal should be understood, although very often it isn't.

A plane has direction only in the sense of its normal.
 

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