Name for DE given by law of gravitation

  • Thread starter Thread starter Tac-Tics
  • Start date Start date
  • Tags Tags
    Gravitation Law
Tac-Tics
Messages
816
Reaction score
7
Is there a name for the DE given by Newton's law of gravity:

f''(x) f(x)^2 = -1

?
 
Physics news on Phys.org
Tac-Tics said:
Is there a name for the DE given by Newton's law of gravity:

f''(x) f(x)^2 = -1

?

Forget about the physics, this is a non linear second order DE. The given DE looks like it can be solve by separating the variables.
 
Tac-Tics said:
Is there a name for the DE given by Newton's law of gravity:

f''(x) f(x)^2 = -1

?
I don't know of any specific "name" for it but. since the independent variable, x, does not appear explicitely, it can be solved using "quadrature":
Let y= f'(x). Then f"(x)= y'= dydx= (dy/df)(df/dx) (by the chain rule)= (dy/df)y. Thus, your equation becomes yf^2 dy/df= -1, a separable first order equation. y dy= -df/f^2. Integrate both sides to find y as a function of f and then integrate y= f(x) to find f.
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
Back
Top