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Navier-stokes equation (fluid mechanics)

  1. May 31, 2006 #1
    i'm revising for my exams, and i didn't go to many of my fluids lectures, now i'm well confused. in the navier-stokes equation for viscous fluid flow, there is a term:

    v(del squared)u

    where v is the kinematic viscosity and u is the velocity field of the fluid. at this point in my notes, the lecturer seems to start doing crazy things which don't make sense.

    first of all, its (del squared)u, not (del squared)(dot)u. i thought (del squared)u only had any meaning if u is a scalar field, but its not, its a vector field. what does this mean?
     
  2. jcsd
  3. May 31, 2006 #2

    arildno

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    [itex]\nabla^{2}[/itex] is a differential operator that perfectly well can be applied to a vector.
     
  4. May 31, 2006 #3

    Gokul43201

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  5. Oct 10, 2010 #4
    V.delV is convection accelaration term in NSE it is the major source for non-linearity of the equation

    You can work it out by

    (V.del)V or V.(del V) both methods are same
     
  6. Oct 11, 2010 #5
    I believe the OP was asking about the viscous dissipation term not the convective term.
     
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