Solve the Volume of an Open Box with a Square Base | Neat Function Problem

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In summary, the problem is to find the minimum amount of material needed to construct an open box with a square base of length x and a volume of 38 cubic feet. This can be expressed as a function of x by finding the height of the box, which is h = 38/x^2. The area of the net can then be expressed as A = x^2 + 4xh, which can be minimized to find the least amount of material needed. Alternatively, a graphing program can be used to determine the optimal value without the use of calculus.
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Homework Statement



An open box wit ha square base is required to have a volume of 38 cubic feet. Express the amount A of material that is needed to make such a box as a function of the length x of a side of the square base. We need to find the solution for the least amount of material used.

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The Attempt at a Solution

 
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Initially, your question description seems incomplete. Do you have a preformed net which merely needs to be folded into the box form? You made no comment related to the height of this box with the square base of x by x. Better----> an expression for height can be made. h*x*x=38. h is the height. If A is area of the net, then an expression can be made for this area from the numbers of h and x.

note: I tried to make a 'strike-through' of the first sentence but the tagging seems to not work.
 
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  • #3
After trying that exercise myself, the original question belongs better in the Calculus board. The solution process yields a rational expression; you want to minimize the Area function.

On the other hand, if you would use a graphing program, you can determine a good value fairly easily without the use of Calculus.
 
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1. What is the formula for finding the volume of an open box with a square base?

The formula for finding the volume of an open box with a square base is V = l^2h, where l is the length of one side of the square base and h is the height of the box.

2. How do you solve for the volume of an open box with a square base?

To solve for the volume of an open box with a square base, you first need to measure the length of one side of the square base and the height of the box. Then, plug these values into the formula V = l^2h and solve for V.

3. Can you provide an example of solving for the volume of an open box with a square base?

Yes, for example, if the length of one side of the square base is 5 cm and the height of the box is 10 cm, the volume would be V = (5 cm)^2 * 10 cm = 250 cm^3.

4. How is the volume of an open box with a square base different from a closed box?

The volume of an open box with a square base is different from a closed box because the open box does not have a top, so the volume would not include the area of the top surface. Additionally, the open box has an opening that allows for items to be placed inside, while a closed box is fully sealed.

5. What is the importance of finding the volume of an open box with a square base?

Finding the volume of an open box with a square base is important in many real-life applications, such as packaging and shipping products, designing storage containers, and calculating the amount of space an object will occupy. It allows for efficient use of space and helps in planning and organizing materials.

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