Need a little more help

  • Thread starter ashleyk
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  • #1
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Main Question or Discussion Point

Let f(x)= (2x-5)/(x^2-4)

I need help on finding the horizontal asymptote. I have already found the vertical. (I realize this doesn't really involve calculus but I already did other part of the problem that involved a derivative)
 

Answers and Replies

  • #2
Pyrrhus
Homework Helper
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the horizontal asymptote is

[tex] \lim_{x \rightarrow \infty} \frac{2x - 5}{x^2 -4} = 0[/tex]

The horizontal asymptote is

[tex] y = 0 [/tex]
 
  • #3
789
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when the power in the denominator is larger than the numerator, you have a horizontal asymptote at y = 0.
 
  • #4
13
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The general idea is to multiply the numerator and denominator by the inverse of x raised to the largest power of the denominator. Then, evaluate the limit.
 
  • #5
740
13
ya divide the numeraator & denominator by (1/x^2) & get that the numerator --> 0 as x --> infinity, and the denominator --> 1 or something. so the horizontal asymptote is y=0
 

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