Need HELP equation of motion with variable acceleration

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Homework Help Overview

The problem involves a particle dropped into oil, where its acceleration is affected by gravitational force and resistance from the oil. The original poster seeks to find the position as a function of time, given the equation of motion that includes variable acceleration.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to solve a second-order differential equation derived from the motion of the particle but encounters issues with determining constants, leading to unexpected results. Some participants suggest reinterpreting the problem as a first-order differential equation related to velocity, questioning the necessity of the second-order approach.

Discussion Status

Participants are exploring different interpretations of the equation of motion. While some guidance has been offered regarding the nature of the differential equation, there is no explicit consensus on the best approach to take. The original poster expresses frustration over their current method and seeks clarification on their misunderstanding.

Contextual Notes

The original poster has provided limited information about their calculations, which complicates the ability of others to identify specific errors in their reasoning.

Behroz
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Homework Statement


A particle is dropped from rest, at the surface, into a tank containing oil
The acceleration of the particle in the oil is a = g – kv
where g is the gravitational acceleration and –kv being denoted by
the resistance put on the particle by the oil.
Solve for x as a function of time!


The Attempt at a Solution


I'm attaching an image file containing my calculations.
As can be seen I get a differential equation of the second order
but as I proceed to solve this equation and try to determine the
constants the whole thing turns into ZERO?!? What am I doing wrong??
 

Attachments

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You don't need to consider this as a 2. order diff. equation. You can view the equation as

[tex]\ddot{x} = g - k\dot{x}[/tex]
or
[tex]\dot{v} = g - kv[/tex]

The second equation is just a 1. order diff. equation with respect to the velocity v.
 
P3X-018 said:
You don't need to consider this as a 2. order diff. equation. You can view the equation as

[tex]\ddot{x} = g - k\dot{x}[/tex]
or
[tex]\dot{v} = g - kv[/tex]

The second equation is just a 1. order diff. equation with respect to the velocity v.

Yeah, you're right.. but one SHOULD be able solve it by puting it up as a second order right? I just want to know what I'm doing wrong, it really bugs me.
 
what have you got? Kind of hard to know what's wrong when we just have a generic list of eqns...
John S
 

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