A skier on a slope inclined at 4.7Degrees to the horizontal pushes on ski poles and starts down the slope. The initial speed is 2.7m/s. The coefficient of kinetic friction between skis and snow is 0.11. Determine how far the skier will slide before coming to rest.
Mew(k) = F(k)/F(N)
v2^2 = v1^2 + 2a(d)
I can't really think of others that would apply.
The Attempt at a Solution
At first I tried multiplying the initial velocity into the angle given to get :
2.7*(cos4.7) = 2.6909m/s
But I am not sure how to go from there, or even if I am on the right path here. I assume that acceleration of gravity will be 9.8m/s^2 so I could possibly get the Force through multiplying initial velocity into gravity :
(9.8)*(2.7(cos4.7)) = 26.37082 N