Need Help Finding Magnitude of Uniform Cylinder

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SUMMARY

The discussion focuses on calculating the magnitude of the acceleration of a uniform cylinder with a mass of 2.7 kg and a radius of 0.25 m as it descends while unwinding a string. The relevant equations include the torque equation T r = I a and the force equation T - mg = ma. By applying these equations, the acceleration of the center of mass is determined to be 9.8 m/s², confirming that the downward linear acceleration matches the acceleration due to gravity, neglecting the mass of the string and air resistance.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with rotational dynamics and torque
  • Knowledge of moment of inertia (I) for a cylinder
  • Basic algebra for solving equations
NEXT STEPS
  • Study the concept of torque in rotational motion
  • Learn about the moment of inertia for different shapes, particularly cylinders
  • Explore the relationship between linear and angular acceleration
  • Investigate real-world applications of rotational dynamics in engineering
USEFUL FOR

This discussion is beneficial for physics students, mechanical engineers, and anyone interested in understanding the dynamics of rotating bodies and their linear motion.

Sam
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A uniform cylinder with a mass of 2.7 kg and a radius of 0.25 m is suspended by a string wrapped around it. As the cylinder descends, the string unwinds from it. What is the magnitude of the acceleration of the center of mass of the cylinder in m/s2? (Neglect the mass of the string and air resistance).



Hint:
The tension on the string acts as a torque about the center of mass and an upward force.
T r = I a
T - mg = ma
a = -a/r

Solving these gives a very simple answer.

NOTE THAT THE QUESTION ASKS FOR THE MAGNITUDE ONLY
 
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I think the downward linear acceleration of the cylinder is 9.8 m/s^2, but I'm not good with rotational motion.
 

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