Need Help with 11 multiple choice Problems for Review

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Homework Help Overview

The discussion revolves around a set of 11 multiple choice problems, with participants reviewing and questioning the answers provided by the original poster. The subject area appears to involve physics concepts related to motion and speed.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are examining specific answers to the multiple choice questions, questioning their validity and suggesting alternatives. There are discussions about the implications of speed and distance in the context of the problems.

Discussion Status

Some participants have expressed skepticism about certain answers, particularly for questions 6, 8, 10, and 11. There is an ongoing exploration of the reasoning behind these answers, with attempts to clarify and interpret the problems further.

Contextual Notes

There is a mention of answers being provided by a friend, which may indicate a reliance on external help. Participants are also seeking clarification on the reasoning behind the answers rather than simply confirming them.

creedreaper
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Topic can be Closed!

EDITED: Got answers from a friend!
 
Last edited:
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So give us your answers and we will let you know.

AM
 
Andrew Mason said:
So give us your answers and we will let you know.

AM

I already did, please check the bottom side of my first post! Thanks!
 
I think results for question 6 (2), 8 (4), 10 (1) & 11 (1) look questionable.
 
Zryn said:
I think results for question 6 (2), 8 (4), 10 (1) & 11 (1) look questionable.

okay...

But what would u replace them with?
 
anyone?
 
Six: Walking 3 mph for 3 h does not result in walking for 3 m total.

Eight: (3) They won't touch the ground at the same time since one is going up for a while before it is going down. (1) They can't touch the ground at the same time since one will be in the air for longer. (4) They can't have traveled the same distance in air, since one went up and will have thus traveled further than the one that went straight down. (2) When they both touch the ground they will be traveling at what speed?

Ten: I have interpreted the first speed as Miles per Hour, and the acceleration as meters per second per second. 60 M/h --> 66 M/h in 1 min = 6 M/(h*min) = 6/60 M/(min*min) = 6/60 * 1/(60*60) M/(s*s) = 6/60 * 1/(60*60) * 1600 m/(s*s) = (5) None of the Above. Perhaps I'm wrong here?

Eleven: 160m/s --> 220m/s in 1 min = 60 m/(s*min) = 60/60 m/(s*s) = (2)
 

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