Need help with Impulse function and unit step function at singularity

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Discussion Overview

The discussion revolves around the concepts of the impulse function and the unit step function, particularly focusing on their behavior at singularities. Participants are exploring mathematical properties and relationships involving these functions, including limits, derivatives, and integrals.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant expresses confusion about singularity and presents limits involving the unit function and delta function.
  • Another participant provides a correction regarding the LaTeX code for integration from negative to positive infinity.
  • A participant discusses the derivative of a function involving the unit step function and the delta function, seeking clarification on the relationship between them.
  • There is a mention of the Kronecker delta and its properties, with a participant asserting that it is different from the Dirac delta function.
  • One participant initially confuses the Kronecker delta with the Dirac delta function but later corrects themselves.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the singularity functions, with some confusion evident about the distinctions between the Kronecker delta and the Dirac delta function. The discussion does not reach a consensus on the derivative of the impulse function or the properties of the unit step function.

Contextual Notes

There are unresolved mathematical steps regarding the limits and integrals involving the unit step function and delta function. The discussion also highlights potential misunderstandings about the definitions and properties of the delta functions.

phoenixy
I have some trouble wrapping my head around singularity

One of assignment question is to show that the unit function is not defined at 0. To do that, I need to show

[tex]\lim_{\Delta\to0}[u_{\Delta}(t)\delta(t)]=0[/tex]
[tex]\lim_{\Delta\to0}[u_{\Delta}(t)\delta_{\Delta}(t)]=\frac{1}{2}\delta(t)[/tex]


Also, I need to show that the following is identical to u(t)
[tex]g(t)=\int u(t)\delta(t-\tau)d\tau[/tex]
integrating from negative infinity to positive infinity


One more question, what's the derivative of the impulse function?

PS: what's the tex code for integration from infinity to infinity? I tried \int_-\infty^+\infty, but the tex output is messed up
 
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Of course.Click on this

[tex]\int_{-\infty}^{+\infty}[/tex]

and use {} wherever necessary.

Daniel.
 
thanks dex,


still need help with the signularity functions ...
 
Hello very body
i got confused understanding how we can get the derivative of V(t) equal to Hv(t) :


V= (1/R) e^(-t/RC) U(t) its derivative V' = Hv(t) = -(1/R²C)e^(-T/RC) U(t) +(1/R)&(t)
where : U(t) is the unite step fonction and &(t) is the delta fonction
please some help
thanks for your time
 
phoenixy said:
thanks dex,


still need help with the signularity functions ...

Second part:

The Kronecker delta is non zero only when the parameter in its brackets is equal to zero. So for the integral, its only when tao is equal to t that delta(t) is non zero. Set tau=t, and you have the result.

The derivative of the step function is the Kronecker delta function. check this out
http://mathworld.wolfram.com/HeavisideStepFunction.html
 
It is Dirac Delta function that is mentioned here. Kronecker Delta is different.
 
tanujkush said:
Second part:

The Kronecker delta is non zero only when the parameter in its brackets is equal to zero. So for the integral, its only when tao is equal to t that delta(t) is non zero. Set tau=t, and you have the result.

The derivative of the step function is the Kronecker delta function. check this out
http://mathworld.wolfram.com/HeavisideStepFunction.html

Oh sorry, I meant the Dirac delta function, not the Kronecker, my bad.
 

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